Shell Programming and Scripting

I am running my script from "/abc/" this path and it has no ".csv files" but has a ".txt" files namely temp1.txt
My script goes as below, wherein it is suppose to find files with *.txt extension and *.csv extension in another path namely "/abc/xyz/":

Code:

#!/bin/ksh
PATH1="/abc/xyz/"
value="*.csv *.txt"
for THISTEMPLATE in $value
do
   THISTEMPLATE=`echo "$THISTEMPLATE" | tr "%" "?"`
  echo "thistemp = $THISTEMPLATE"
  for OLDFILE in `find $PATH1 -name "$THISTEMPLATE" -type f`
  do
    echo "oldfile= $OLDFILE"
   done
done

>OUTPUT:
thistemp = *.csv
thistemp = temp1.txt
But if you see the output the variable contains the filename "temp1.txt" instead of just "*.txt", how can i modify the script so that
the variable THISTEMPLATE takes only *.txt instead of the whole filename.

Change this line:

Code:

for THISTEMPLATE in $value

with:

Code:

ls $value 2>/dev/null | while read THISTEMPLATE

after changing,
the output is just displaying this
OUTPUT
thistemp = temp1.txt

can someone please help

Code:

 
for THISTEMPLATE in "*.txt" "*.csv"

But that would not make it dynamic.

I dont want to hardcode the value in the for statement..

Is there any other way ?

From your first post:
What are you expect if you have only one .txt file?

temp1.txt is present in /abc/ , this is the place from where i am running the script.

but i would like to find *.txt files in another location /abc/xyz/

The output should display all the ".csv" and ".txt" files in present in /abc/xyz/, instead of /abc/