Shell Programming and Scripting

Hi,

Can someone guide me to write a unix script for getting a hour out of a date command and validating hour to see if its > 7 and < 16. if hours is >7 and <16 then assign a variable value of 0730 and if hour is >16 then assign a variable value of 1630?

Help appreciated.

Thanks in advance.

Zulfiqar

sure, how about this for a start? if you read it, it will show you how to use if/else, how to cut strings...etc

Thanks. To start with I wrote this and executed (Not sure though its correct or not):

#!/bin/bash
$HR=date +%H;
if [$HR -gt 7];
if [$HR -lt 16]; then
sendevent -E SET_GLOBAL -G GOMAN_HR=0730
else if [$HR -gt 16];
sendevent -E SET_GLOBAL -G GOMAN_HR=1630
fi
fi
fi

I am getting following error:
./GOMAN_HR.sh: line 2: =date: command not found
./GOMAN_HR.sh: line 8: syntax error near unexpected token `fi'
./GOMAN_HR.sh: line 8: ` fi'

Any help or guidance?

Thanks.
Zulfiqar

try this:

Code:

HR=$(date +%H);

and delete the last "fi".
Regards

That didn't work. Then I tried following:

:/export/home/zdholkawala $ sh -v GOMAN_HR.sh
#!/bin/bash
HR=`date +%H`;
if [$HR -gt 7];
if [$HR -lt 16]; then
sendevent -E SET_GLOBAL -G GOMAN_HR=0730
else if [$HR -gt 16]; then
sendevent -E SET_GLOBAL -G GOMAN_HR=1630
fi
fi
fi
GOMAN_HR.sh: syntax error at line 11: `fi' unexpected

Even removing last fi doesn't work here. Any help?

well, if you really read it, you can see this example (4-3) how to assign to variable the output of a command such as ls. it applies to date command as well...pls read it again, from start to finish.

Thanks. Now new error:

Code:

#!/bin/bash
HR=`date +%H`;
if ["$HR" -gt 6] && ["$HR" -lt 16]; then
  sendevent -E SET_GLOBAL -G GOMAN_HR=`0730`
  exit 0
else if ["$HR" -gt 15]; then
  sendevent -E SET_GLOBAL -G GOMAN_HR=`1630`
  exit 0
  fi
fi

GOMAN_HR.sh: [07: not found
GOMAN_HR.sh: [07: not found

Not sure where its coming from?

Thanks.