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# 1  
Old 05-14-2009
More formatted string
In a large file i need last line of the file but I want ignore first charcter, ignore leading zeros after first character and print the remaining character as such. Is something i can do it by tail or wc?
cat test1
....
......
8000003687
cat test2
....
......
8000538990
o/p
3687
538990
# 2  
Old 05-14-2009
Code:
awk 'END{print $0}' file| sed 's/^[0-9]0*\(.*\)/\1/g'


cheers,
Devaraj Takhellambam
# 3  
Old 05-14-2009
Or:

Code:
awk 'END{printf("%d\n",int(substr($0,2)))}'

Regards
# 4  
Old 05-14-2009
if its large file, use tail
Code:
tail -1 largefile | sed ......

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