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SED or AWK "append line to the previous line"

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# 1  
Old 05-14-2009
SED or AWK "append line to the previous line"
Hi,

How can I remove the line beak in the following case if the line begin with the special char “;”?

TEXT

Text;text
;text
Text;text;text


I want to convert the text to:

Text;text;text
Text;text;text



I have already tried to use “sed”, but the command only replace the first char one the line!


cat text | sed -e :a -e '$!N;s/^;/ /;ta' -e 'P;D'

Text;text
text
Text;text;text


Any suggestion ??

Thanks in advance!
# 2  
Old 05-14-2009
Code:
# awk 'ORS=/^;/?"\n":" "' file
Text;text ;text
Text;text;text

# 3  
Old 05-14-2009
Thanks ghostdog74 for your fast reply, but unfortunately if the file includes more line

Exp.

Text;tex
;text;
Text;text;text;
010020;789
test;test;test


then the command delete all the line breaks.

cat text | awk 'ORS=/^;/?"\n":" "'

Text;tex ;text;
Text;text;text; 010020;789 test;test;test

Output File should be:

Text;tex;text;
Text;text;text;
010020;789
test;test;test

Any suggestion in this case ??
# 4  
Old 05-14-2009
What would be a 100% indicator that it is the beginning of a line? A line beginning with a upper case T?
# 5  
Old 05-14-2009
The 100% indicator in my project file is [[:digit:]]!
All lines beginning with the upper case [0-9].
# 6  
Old 05-14-2009
I use the following command now: awk '/^;/ {sub(/^;/,""); getline t; print $0 t; next}; 1'
but unfortunately the next line will be appended to the pattern line and not the the pattern line to the preview.



awk '/^;/ {sub(/^;/,""); getline t; print $0 t; next}; 1' text

Text;tex
text;Text;text;text;
010020;789
test;test;test


output file should be:

Text;tex;text
Text;text;text;
010020;789
test;test;test



Is there a way I can append the line with the beginning “^;” to the preview line!


Many thanks!
# 7  
Old 05-14-2009
if you have Python, here's an alternative solution
Code:
#!/usr/bin/env python

data=open("file").read().split("\n")
for n,items in enumerate(data):
    if items.startswith(";"):
        data[n-1]= data[n-1]+items
        data.pop(n)
print '\n'.join(data)

output:
Code:
# more file
Text;tex
;text;
Text;text;text;
010020;789
abcdefg; sdf;
;text;
Text;text;text;
010020;789
test;test;test

# ./test.py
Text;tex;text;
Text;text;text;
010020;789
abcdefg; sdf;;text;
Text;text;text;
010020;789
test;test;test
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