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awk after words

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# 1  
Old 05-11-2009
awk after words
hi sorry, newbie for scripting..
the text file: abcdefghijk%%$%^U^%234454234

I got awk script:

awk ' ($1 == "abcd")

the output only show: abcd

I tried using asterix: awk ' ($1 == "abcd*") but same output abcd only...

how can I get all of the line ??
# 2  
Old 05-11-2009
Do you want to get entire line as output?
# 3  
Old 05-11-2009
Quote:
Originally Posted by naw_deepak
Do you want to get entire line as output?
hi yes.. but I do not want to make like

awk ' ($1 == "abcdefghijk%%$%^U^%234454234")

its too long if I do that.. any other way to shortened it up?
# 4  
Old 05-11-2009
"==" is equality. use ~ for regular expression.
# 5  
Old 05-11-2009
Quote:
Originally Posted by ghostdog74
"==" is equality. use ~ for regular expression.
so u mean I have to use like this?
awk ' ($1 ~ "abcdefghijk%%$%^U^%234454234")
# 6  
Old 05-11-2009
$1 ~ /abcd*/
# 7  
Old 05-11-2009
Quote:
Originally Posted by ghostdog74
$1 ~ /abcd*/
oh.. let me try first.. thank you Smilie
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