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reading multiple files

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# 1  
Old 05-04-2009
reading multiple files
Hello

I have a requirement where i have to loop through certain directory which will have multiple files. After looping through i have to make a list of file names exisitng in the directory and write them to a sequental file and each file should be delimited by ^%^

i.e If i have 3 files A, B,C in a directory called Files then i have to loop through the Files directory and write the file names to a .txt file with each file name is delimited by ^%^ as below

A^%^B^%^C

Regards
Dsdev_123
# 2  
Old 05-04-2009
One way:
Code:
cd /directory
ls | awk '{ printf("%s^%%^", $1) }' | sed 's/\^\%\%$//' > /path/to/file.txt

# 3  
Old 05-04-2009
Try this:

Code:
 ls | awk '{printf "%s%s", NR==1?"":"^%^",$0}'

# 4  
Old 05-05-2009
Quote:
Originally Posted by jim mcnamara
One way:
Code:
cd /directory
ls | awk '{ printf("%s^%%^", $1) }' | sed 's/\^\%\%$//' > /path/to/file.txt


Hi when i executed this i am getting
A^%^B^%^C^%^

The last filename should not get ^%^ at the end.

Thanks for your reply
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