[Bash]Function returning a boolean


 
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# 1  
Old 04-29-2009
[Bash]Function returning a boolean

Hello all,

I would like to know if it is possible to return a the result of a boolean expression from a function like this
Code:
function()
{
  # some code
  return [ $nb1 -lt 100 ] || [ $nb2 -lt 100 ]
}

and what will be the return value ?

Thank you for help.
# 2  
Old 04-29-2009

Code:
func()
{
  # ...
  [ $nb1 -lt 100 ] || [ $nb2 -lt 100 ]
}

The return code will be 0 (=success) if either nb1 or nb2 is less than 100.
# 3  
Old 04-29-2009
Alright thank you. I have another question though, now that i have my result is it possible to use it in another test in this way :

Code:
function_boolean
bool=$?
while [ $bool ] && [ boolean expression ]; do
  # ...
done

# 4  
Old 04-29-2009

Did you try it?

Did it work?
# 5  
Old 04-29-2009
Quote:
Originally Posted by dolphin06
Alright thank you. I have another question though, now that i have my result is it possible to use it in another test in this way :

Code:
function_boolean
bool=$?
while [ $bool ] && [ boolean expression ]; do
  # ...
done

Code:
bool=$?
while [ $bool ]

this will always be true. so you may want to compare like $bol > 0 or $bol =0 or something as you want.


Code:
bool=$?
while [[ $bool > 0 &&  true ]]; do
  # ...
done

cheers,
Devaraj Takhellambam
# 6  
Old 04-29-2009
Yes it tried, but didnt work the way i want, but i dont know where i m wrong even i m echoing some values.
# 7  
Old 04-29-2009
Alright its working now that i add the comparison operator.
Thanks guys.
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