Shell Programming and Scripting

Hi Gurus,
Could you please help me to create a shell script that will be started by a cron job once every night at 24.00 h (that should bee easy)

The shell script should control every 30 seconds the name of a process, and when the process doesn't run anymore it should execute a few further commands and then stop.

Hello,

Please go through the crontab basics, give it a try first and please explain as much as you can in the post. Check out the link below.

Unix Crontab - setting up cron jobs using crontab

Many thanks

as i said crontab will be easy... I am having problems with the shell script loop

You can have a script which is fired at 2400 hrs , the Pesudocode for that script is as below

If you provide me details then I can write a script.

while [ grep(ing) for the process you want.]
do
if that process is not found
then
do the necessary steps you wish to do
else
sleep 30
fi
done

Cheers
Sachin Raje.

ok. i m now up with this solution.
----------------
#!/bin/csh
while (`ps -ef | grep -c "[P]opChar"` == "1")
echo "PopChar is up"
sleep 30
if (`ps -ef | grep -c "[P]opChar"` == "0") then
echo "The PopChar utility not running"
endif
end
----------------

the problem I have now is that the part

echo "The PopChar utility not running"

not will be not will be executed if the script starts
and PopChar isn't running. how can i establish this functionality

How long to you wish to keep on looking for the PopChar utility if it is not found ?
That answer will be your and conditon in the while loop to break and exit.
Hope that helps.

cheers
Sachin Raje.

Try this - not tested

Code:

#!/usr/bin/sh
echo "start"
if [ `ps -ef | grep -c "sleep"` -gt 0 ];
then
flag=true
else
echo "POPchar is down"
echo "Exiting now"
flag=false
fi
while [ "$flag" = "true" ]
do
if [ `ps -ef | grep -c "sleep"` -gt 0 ]; then
echo "POPChar is running"
flag=true
sleep 30
else
echo "POPchar is down"
flag=false
fi
done

cheers,
Devaraj Takhellambam