Shell Programming and Scripting

Hi all
Iam new to the UNX basically iam jave Dev...
could you please give any suggestion for the below requirement
i have folder like INDIA in that i have sub holder like A, B,C,D,.....and again i have subholer like A/1.java, b/2/java.....
INDIA/A/1.java
INDIA/B/2.java
INDIA/C/3.java
..............
...............
but the 1.java,2.java,3.java have the same line numbers(structure)
i want read line number 3 from each file and i need to save this line 3 (from each file) in other file
please give any suggestion/ideas to reach above requirement.
thanks

for file in `ls ${PWD}/INDIA/*.java`
do
head -n 3 $file | tail -1 >> sometempfile
done
cat sometempfile

I think this code shud do the job.

say you have compplete file names from where you want to extract the 3rd line
and its saved in file called list.txt

#cat list.txt
INDIA/A/1.java
INDIA/B/2.java
INDIA/C/3.java
.
.

:Code:

while read line
do
head -3 $line | tail -1 >> final.txt

done < list.txt

echo " `cat final.txt`"

Again Hi All
sorry to say that
"${PWD}/INDIA/*." its not a holder
its a Directory like
/INDIA is directory
/SSS is sub directory
/*.java is scripts
when i tryed with diliph its giveing error cause of its not folder it directory
please give susggestion how opent this directory
like
"/INDIA/SSS*/Scr*/*.java"
thanks

you can use the bellow to find all the files (*.java) in current dir and its sub dir. Then you can use the code i mentioned already

find ./ -name *.java > list.txt

just try directing the path to the folders containing .java files.
U can try

for file in `ls /INDIA/SSS*/Scr*/*.java`

Code:

find . -name "*.java" | while read line;do sed -n '3p' $line; done > out.txt