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How to type a dot(.) instead of character?

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# 1  
Old 04-24-2009
Question How to type a dot(.) instead of character?
Hi,

I want to connect a Oracle databse through unix shell script.
When I will execute a shell script it will ask for user name and password to connect the databsae.
At the time of entering the password field value, it willl display the characters like star(*), dot(.) instead of exact character.

How I will do ?
Please help me because this one urgent to fix in the code .

Regards
Rajesh
# 2  
Old 04-24-2009
Code:
printf "%s" "Please Enter Username:"
read auser

printf "%s" "Please Enter Password:"
stty -echo
read apassword

This suppresses printing of password altogether.
# 3  
Old 04-24-2009
Here is one way of doing what you want. Trick is your version of echo has to support '\c' functionality. Replace the dot with an asterik if that is what you want outputted.
Code:
#!/bin/bash

passwd=""
omodes=`stty -g`

/bin/echo "Enter Password: \c"
while :
do
   stty raw
   c=$(dd bs=1 count=1 2>/dev/null)
   stty -raw

   # break out of loop if CR found
   [[ -z $(echo $c | tr -d "\015") ]] && break

   stty echo
   /bin/echo ".\c"
   passwd=${passwd}${c}
   stty -echo
done

stty $omodes

echo
echo "Password entered: $passwd"

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