Shell Programming and Scripting

I'm new to shell programming and am trying to delete/replace certain characters in a pattern. Here's an example of what I'm trying to do.

input file has multiple lines of the following form

#0,v,g,n,n,n,(stuff....)
#1,x,g,n,c,n,(stuff..blah..blah)
#2,x,g,x,x,m,(stuff..blah)
...
#25,x,g,x,x,n,(stuff...)

and I want to output to be

#0,v,g,n,n,(stuff...)
#1,u,g,n,c,(stuff....)
#2,u,g,n,n,(stuff...)
.....
#25,u,g,n,n,(stuff....)

Basically I need to replace the first occurrence of x with u then the rest with n. This part I was able to do. Then I need to remove the last letter from the pattern (n or m) and leave the rest. Is there some way I can search for say ,.,.,.,.,., and then remove the last ., without knowing what character it will be or which occurrence. Say read the pattern into a variable and then remove the last character through its index or something.

Thanks for any help on figure this out

D

try this

sed '
s/x/u/1
s/x/n/g
s/\(^[^,]*,\)\([^,]*,\)\([^,]*,\)\([^,]*,\)\([^,]*,\)\([^,]*,\)\(.*$\)/\1\2\3\4\5\7/g' sedfile


cheers,
Devaraj Takhellambam