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Shell Programming and Scripting

Getting first word from a line

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# 1  
Old 04-21-2009
Bug Getting first word from a line
How can i get first word form a line.

for eg.
I have this line:
"nbs2yth 3123 1 fsfsa thisissamletext"

I want to store the first word(here "nbs2yth") in a variable.

How can i do this, either using grep or awk commmand.
# 2  
Old 04-21-2009
with bash
Code:
# aline="n=nbs2yth 3123 1 fsfsa thisissamletext"
# set -- $aline
# echo $1
nbs2yth

with awk
Code:
echo "$aline" | awk '{print $1}'

Last edited by ghostdog74; 04-21-2009 at 06:59 AM.. Reason: wrong quotes
# 3  
Old 04-21-2009
To strip out the first space till the end:

Code:
var=${string%% *}

Regards
# 4  
Old 04-21-2009
var1="nbs2yth 3123 1 fsfsa thisissamletext"
echo $var1 | awk -F" " '{print $1}'
# 5  
Old 04-21-2009
Quote:
Originally Posted by ganapathi.t
var1="nbs2yth 3123 1 fsfsa thisissamletext"
echo $var1 | awk -F" " '{print $1}'

no need -F" "
# 6  
Old 04-21-2009
You are correct, no need to give -F" ", as the default delimiter for awk command is "<space>". But it is always better practice to use -F" " to specify the delimiter what we are passing...

-regards.
# 7  
Old 04-21-2009
Quote:
Originally Posted by ganapathi.t
You are correct, no need to give -F" ", as the default delimiter for awk command is "<space>".
-regards.
not just space.
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