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passing argument to shell script that reads user inputs

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# 1  
Old 04-09-2009
passing argument to shell script that reads user inputs
Hi,
Lets say I have a script "ss" which does this

read abc
echo $abc
read pqr
echo $pqr

Now if I want to pass and argument to only "abc" how do I do it.
If I do

echo "somevalue" | ss, it does not prompt for pqr and its value comes out as blank.

Any help is appreciated

Thanks
P
# 2  
Old 04-09-2009
Try this:

Code:
read abc
echo $abc

read pqr < "/dev/tty"
echo $pqr

Regards
# 3  
Old 04-09-2009
I thought of trying heretext as follows:
Code:
./ss << EEOOFF
abc
EEOOFF

Where the first read will get the value abc, the second read waits for user input.
# 4  
Old 04-09-2009
@Franklin52:
Thanks for your reply. But I can't modify the script. All I have to play with is how the argument is passed Smilie

P
# 5  
Old 04-09-2009
@Tony:
I tried that, but it doesnt wait for the prompt at the second instance. It prints a blank value

P
# 6  
Old 04-10-2009
Worked for me In Linux in bash.
# 7  
Old 04-10-2009
Try this:

Code:
(echo "abc-value"; cat -) | uncooperative-script

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