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Perl help - Searching for a pattern and return the position

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# 1  
Old 04-08-2009
Perl help - Searching for a pattern and return the position
Hi,
I need to search a file, in each line I need to check for occurance of '1' from a particular position through the next 32 bytes. If 1 is found, i need to return the position. Here is an example of the file and the output i need. Please help. I'm new to perl and unix.

File:
Code:
12341234567890123400100011001000100010000000001000233493849318
12341234567890123410000000000000100000001110000000238437483291
12341234567890123401000000010000000010000000001001028282783828
12341234567890123400000010000000010000001000000001122389393939

In the above file, starting from 19th byte i need to check if '1' is present in the next 32 bytes. I need to position as the output, each separated by ';'.
Here is the output I am expecting.

Code:
003;007;008;011;015;019;029;
001;015;023;024;025;
002;010;019;029;032;
007;016;023;032;

The first line starts with 003 since 1 is found in the 3rd position after the 19th byte of that line.
# 2  
Old 04-08-2009
next time, some effort on your part to solve your programming requirements would be nice to see, even if they do not work.

Code:
while(<DATA>){
   my $t = substr($_,18,32);
   while($t =~ /1/g) {
      printf "%03d;", pos($t);
   }
   print "\n";
}
__DATA__
12341234567890123400100011001000100010000000001000233493849318
12341234567890123410000000000000100000001110000000238437483291
12341234567890123401000000010000000010000000001001028282783828
12341234567890123400000010000000010000001000000001122389393939

make sure you have the "g" on the end of the regexp or you will put the script into an infinite loop.
Last edited by KevinADC; 04-08-2009 at 06:11 PM..
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