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Cron job to move file from one directory to another

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# 1  
Old 04-08-2009
Cron job to move file from one directory to another
Hi,

I have following directory structure

Media (Inside media directory I have two folders namely videos and images)
-->videos
-->images

Inside media directory I have some video files with extension .mp4 and images with extension of .jpg and .jpeg

I want to write a cron job which will run every 30 min and will move all .mp4 files inside media directory to videos directory and images files to images directory.


Can anyone please help me with this.


Thanks!
# 2  
Old 04-08-2009
Try:
Code:
#!/bin/bash
find Media -type f -maxdepth 1 -name "*.mp4" -exec mv {} Media/videos \;
find Media -type f -maxdepth 1 -name "*.jpg" -exec mv {} Media/images \;
find Media -type f -maxdepth 1 -name "*.jpeg" -exec mv {} Media/images \;

Put that in a script, e.g. /usr/local/bin/movemedia.sh
and then add a crontab line:
Code:
1,31 * * * * /usr/local/bin/movemedia.sh >> /var/log/movemedia.log 2>&1

If you are using Linux then you want to rotate the log file each day by creating a file: /etc/logrotate.d/movemedia containing something like:
Code:
/var/log/movemedia.log {
        rotate 14
        daily
        missingok
}

Which will move movemedia.log to movemedia.log.0 up to movemedia.log.14 so keeping the last 14 day's logs.
Last edited by TonyFullerMalv; 04-08-2009 at 03:46 PM..
# 3  
Old 04-08-2009
Thanks a lot for your help.
Just one question.

I know the exact path of media directory. How can incorporate that path in this command.

$sDirectory = "/www/sites/projects/media";
$sVideos = "/www/sites/projects/media/videos";
$sImages = "/www/sites/projects/media/images";

I am not very sure of how can i use this?

$sDirectory -type f -maxdepth 1 -name "*.mp4" -exec mv {} $sVideos \;
# 4  
Old 04-08-2009
Quote:
Originally Posted by tusharkale
$sDirectory -type f -maxdepth 1 -name "*.mp4" -exec mv {} $sVideos \;
Yes with the find:
Code:
 find $sDirectory -type f -maxdepth 1 -name "*.mp4" -exec mv {} $sVideos \;

and your lines at the before the find lines in the script (note no spaces on either side of the "="):
Code:
$sDirectory="/www/sites/projects/media"
$sVideos="/www/sites/projects/media/videos"
$sImages="/www/sites/projects/media/images"

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