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can any one explain the meaning of the below code ?

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Top Forums Shell Programming and Scripting can any one explain the meaning of the below code ?
# 1  
Old 04-02-2009
can any one explain the meaning of the below code ?
Code:
while getopts :g:l:h: KEY $*
do
   case $KEY
   in
       g) NAME=$OPTARG ;;
       l) LAB=$OPTARG ;;
       h) HD=$OPTARG ;;
       *) echo "Illegal option: $OPTARG"
          echo "$usage"
          exitStatus=1
          exitGrace
   esac
done

Last edited by jim mcnamara; 04-02-2009 at 11:16 AM.. Reason: PLEASE use code tags. Thanks
# 2  
Old 04-02-2009
Hello there,

Your script accepts three command line options -l -h and -g and each of these options requires an argument. The case inside checks the validity of the inserted values. You will run something like this

Code:
./yourscript -g <NAME> -l <LAB> -h <HD>


Regards
Smilie
# 3  
Old 04-03-2009
thanks a lot
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