Shell Programming and Scripting

If it works when run separately, but not in the larger script then obviously the problem is related to something before.

Then it is not being run by bash!

(There is no point to using the -e option with -n1; -e enables line editing, but since you are only allowing a single character to be entered, it is not possible to edit the line.)

Please put code inside [code] tags.

bash-3.00# cat test.sh
#!/bin/bash

The following code is bloated and convoluted; that can make debugging difficult. Please replace it with the snippet I suggested before.

        until [ -n "$CONFIGCACHE" ] && [ -n "$prompt" ] && [ -z `echo $CONFIGCACHE | sed -e 's/[YN]//g' ` ]
        do
                echo -n "Do you want to configure Cache Manager? [Y/N] "
                read -e -n 1 CONFIGCACHE
                echo ""
                prompt=1
        done

bash-3.00# ./test.sh
Do you want to configure Cache Manager? [Y/N] Y

bash-3.00#

And I repeat: What command line do you use to run it?

If the permissions are 0644, then it isn't being treated as an executable script, but as the argument to a shell command, and it will be run by whatever shell is used on the command line, e.g., /bin/sh scriptname. (That's why I asked how it was being run.)

If you really want to allow the user to enter just one key, either have the packaging script call a wrapper that does use bash to execute the script, or use dd instead of read.

Code:

printf "Do you want to configure Cache Manager? [Y/N] "
[ -t 0 ] && { _STTY=`stty -g`; stty -icanon -echo min 1; }
while :
do
  CONFIGCACHE=`dd bs=1 count=1 2>/dev/null`
  case $CONFIGCACHE in
    [yYnN]) break ;;
  esac
done
[ -t 0 ] && stty $_STTY
echo "$CONFIGCACHE"

echo "Please type the path of the Log directory: (current value: $SB_LOGDIR1)"
readDefault -e SB_LOGDIR1

If you use the -e option, you must run the script with bash. No other shell has it.

This is bash only:

Code:

VARNAME=${!#}

You have bash on your Solaris box, so why not use it?

This is POSIX, but doesn't work in Bourne shell:

Code:

export $VARNAME=$LOCALBUF

.....

I hope you don't use this on your Linux box:

Code:

N=`expr $N + 1`

Bash (like all POSIX shells) has arithmetic built in:

Code:

N=$(( $N + 1 ))