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BASH script question

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# 1  
Old 04-01-2009
BASH script question / create a script that gets a filename as an argument
Hi,

I want to create a script that gets a filename as an argument.
The script should generate a listing in long list format of the current directory, sorted by file size.
This list must be written to a new file by the filename given on the command line.

Can someone help me with this?

Here is my start:

Code:
#!/bin/sh
echo "Please give in the filename"
read NEW_FILENAME
#read the current directory in long listing and sort by filesize (small to big) and writes it to the given filename
ls -l -S -r  > $NEW_FILENAME

But I am kind of stuck.

Thanks for your help so far.
Last edited by I-1; 04-01-2009 at 10:13 AM.. Reason: title unclear
# 2  
Old 04-01-2009
Hi
You can simple use this command, to obtain the list of extant files and directories sorted by size

PHP Code:
ls -al | sort +4 -r > temp.log 
If your OS is HP-UX, you can use:
PHP Code:
 ll | sort +4 -r > temp.log 
Regards
# 3  
Old 04-01-2009
Hi,

I think I allready found the solution ...

Code:
#!/bin/sh
echo "Please give in the filename"
read NEW_FILENAME
#read the current directory in long listing and sort by filesize (small to big) and writes it to the given filename
ls -l -S -r  > $NEW_FILENAME

# 4  
Old 04-02-2009
Glad you found but is you want your script to be a bash script it have to start with:
#!/bin/bash
;-)
# 5  
Old 04-02-2009
Quote:
Originally Posted by laurentv
Glad you found but is you want your script to be a bash script it have to start with:
#!/bin/bash
;-)
I am a n00b when it comes to shell scripting ... but this is one of the things you cant miss when you read teh guides and books on this subject :-)
# 6  
Old 04-02-2009
Hi,

To add a command line arguement to a script try:

listit.sh

#!/bin/sh
if test $# -gt 0; then
target=$1;
else
echo "no output file specified using default.lst"
target=default.lst
fi
ls -l -S -r > $target

You can then run
./listit.sh myfile.lst

If you just run the script without an argument it will use the default.lst file.
# 7  
Old 04-03-2009
If you want this to behave more like a standard unix command line tool, you might want to consider using getopts. For example:

Code:
#!/bin/bash

usage() {
cat <<EOT
Usage: `basename $0` [-f] [-o filename]

    -o file  output to filename.  Default: prompt for filename
    -f       force overwrite if output file already exist
EOT
}

filename=""
force=false
while getopts fo: opt; do
  case "$opt" in
    o) filename="$OPTARG" ;;
    f) force=true ;;
  esac
done
shift `expr $OPTIND - 1`

if [ -z "$filename" ]; then
  read -p "Enter a filename: " filename
fi

if [ -s "$filename" -a $force = "false" ]; then
  echo "ERROR: $filename exists" >&2
  exit 1
fi

ls -lSr > "$filename"

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