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how can i find sqrt of a any number without using expr

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# 1  
Old 03-31-2009
how can i find sqrt of a any number without using expr
hi friends
can any body tell me how can i find sqrt of a any given number without using expr in bash shell
while i am doing i got some errors please take a look
and code is here
x=$((( ( sqrt($1) ) | bc )))
echo $x

Code:
[srinivas@localhost shell-lab]$ sh quadratic-eqn-roots.sh 9
quadratic-eqn-roots.sh: line 12: ( ( sqrt(9) ) | bc ): missing `)' (error token is "(9) ) | bc )")

# 2  
Old 04-15-2009
Heh, That expression is very problematic. Here's one that works. The first argument is a number, which becomes 0 if it's not provided or if it is less than 0. The second argument is the number of decimal places to output -- or 4 if not provided.
Code:
y=$1
scale=4
# Make sure input is a valid number.
test -n "$y" || y=0; test "$y" -ge 0 || y=0
# Make sure scale is some number
test -z "$2" || scale=$2
# calc square root via bc
{ echo "scale=$scale"; echo "sqrt($y)" ; } | bc

# 3  
Old 04-15-2009
MySQL how can i find sqrt of a any number without using expr
vow...great...thanks a lot....
Smilie
# 4  
Old 04-15-2009
you can also use awk
Code:
printf "4" | awk '{print sqrt($0)}'

# 5  
Old 04-15-2009
Thanks..... I was actually just looking for a simple solution to that!

Quote:
Originally Posted by ghostdog74
you can also use awk
Code:
printf "4" | awk '{print sqrt($0)}'

# 6  
Old 04-15-2009
Code:
echo "sqrt($var)" | bc -l" | read root

The bc in Linux exceeds standard: add a -l for all you non-Linux coders.
# 7  
Old 04-16-2009
Ghostdog's solution is better, and can be made even simpler:

Code:
x=`awk "END{print sqrt($y)}" </dev/null`

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