Shell Programming and Scripting

No problem, but I am going to move this thread to "Shell Programming and Scripting" as it is not really AIX-related.

At first you have to change the filter to find also the files with apostrophes in their names. In the following, the first line is the original, the second line into what you should change it:

Code:

ls -1 | grep "[^ ] [^ ]" | while read oldfile ; do
ls -1 | grep "[^ '] [^ ']" | while read oldfile ; do

Second you have to change the replacement mechanism itself: the line where from the old filename the new one is derived. As this starts to get more complex we change from the simple "tr" to "sed:

Code:

newfile="$( print - $oldfile | tr -d ' ')"
newfile="$( print - $oldfile | sed 's/\'//g;s/ //g')"

Ready - that should do it.

I hope this helps.

bakunin

Another approach with awk:

Code:

ls | awk '
{f=$0; gsub("[^A-Za-z0-9.]", "")}
f != $0 { system("mv " f " " $0) }'

First we store the original filename in the variable f and remove the characters, not defined in the class, from the current line (filename). Then we compare the the current line with the original filename and move the file if the name is changed.

Regards

Thanks bakunin,

It's working with a small change, replaced single qoutes to double qoutes.

Hello Srimitta,

You can use the same script given by bacunin and replace the line

" newfile="$( print - $oldfile | tr -d ' ')" as

" newfile="$( print - $oldfile | tr -d ' '| tr -d ''')" "