Shell Programming and Scripting

Hi,

i am trying to copy files except the latest, my script goes here
#! /bin/bash
# to copy control files to a local DR server
# copy latest files of archive
#modified on 26-03-2009
#
--get today date
dt=` date +"%Y_%m_%d"`

--get yesterdays date
adt=`(date --date='1 day ago' +"%Y_%m_%d")`
--destination folder
dtdir=/u02/flash_recovery_area/CRM/autobackup
--source folder
cpdir=/opt/ora_central/CRM/flash_recovery_area/CRM/autobackup

--if no folder exists on todays date in destination then create folder
mkdir -p $dtdir/$dt

slg=/u02/flash_recovery_area/CRM/archivelog
clg=/opt/ora_central/CRM/flash_recovery_area/CRM/archivelog
mkdir -p $slg/$dt

--yesterday date folder found copy files if any missing from the source to destination
if [ -d $slg/$adt ]; then
find $cpdir/$adt/*.bkp -mtime 0 -exec cp -u {} $dtdir/$adt \;
find $clg/$adt/*.arc -mtime 0 -exec cp -u {} $slg/$adt \;
echo "hi"
fi

find $cpdir/$dt/*.bkp -mtime 0 -exec cp -u {} $dtdir/$dt \;
--iam trying to copy files except latest 1 file from todays date folder to target folders
find $clg/$dt/*.arc -mtime 0|sed '$d'| xargs --replace cp -u {} $slg/$dt/
eg:2009_03_26 2009-03_27

please suggest me if any changes can be made to this script to copy latest files except the last new file created from source.

Please put code inside [code] tags.

Please do not include invalid lines within your script; use comments.

Code:

adt=$(date --date='1 day ago' +"%Y_%m_%d")

Or:

Code:

adt=`date --date='1 day ago' +"%Y_%m_%d"`

Check whether the directory exists before calling mkdir:

Code:

[ -d "$slg/$dt" ] || mkdir -p $slg/$dt

I think a very similar question was asked recently. Have you searched the forum?