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Extract sequence blocks

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# 1  
Old 03-25-2009
Extract sequence blocks
Hi,


I have an one-line file consisting of a sequence of 660 letters. I would like to extract 9-letter blocks iteratively:

ASDFGHJKLQWERTYUIOPZXCVBNM

first block: ASDFGHJKL
1nd block: SDFGHJKLQ

What I have so far only gives me the first block, can anyone please explain why?

cat file | awk '{pep=""; for (i=0; i<=NF; i++); (pep=substr($0,i,9)); {print pep}}'


Cheers,
S
# 2  
Old 03-25-2009
"man fold"

Thanks
SHa
# 3  
Old 03-25-2009
Well the problem with "fold" is it (as the name hints) only folds my sequence and gives me 9-letter long blocks.

What I need is to go through the line, letter by letter, and extract 9-letter long blocks...

But thanks anyway, fold with surely be useful to me in the future!
/S
# 4  
Old 03-25-2009
Quote:
Originally Posted by solli
Well the problem with "fold" is it (as the name hints) only folds my sequence and gives me 9-letter long blocks.

What I need is to go through the line, letter by letter, and extract 9-letter long blocks...

But thanks anyway, fold with surely be useful to me in the future!
/S
how's that different from what 'fold' provides?
# 5  
Old 03-25-2009
Let's say my line is: 123456789123456789123456789

fold gives me:
123456789
123456789
123456789

but I need:
123456789
234567891
345678912
# 6  
Old 03-25-2009
ah, ok:
Code:
echo '123456789123456789123456789' | nawk -v len=9 '{l=length; for(i=1;i<=l-len+1; i++) print substr($0,i,len)}'

Last edited by vgersh99; 03-25-2009 at 01:03 PM..
# 7  
Old 03-25-2009
Thanks!
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