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Script works with bash 3.0 but not 3.2.

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Top Forums Shell Programming and Scripting Script works with bash 3.0 but not 3.2.
# 1  
Old 03-20-2009
Script works with bash 3.0 but not 3.2.
Hello,

So my knowledge of bash scripting is not that great and I have been trying to solve this problem on my own for awhile to no avail.



Here's the error I get when running it with an OS that uses bash 3.2.x:

testagain.sh: line 10: *-1: syntax error: operand expected (error token is "*-1")



Here's the script (sorry for the lack of indents not sure how the formatting on this forum works):

Code:
#!/bin/bash

cd /home/sites

for logdir in */logs; do
        
        for access_log in ${logdir}/access_log.*; do
              
                lognum=`echo $access_log | sed -e 's/.*access_log\.//'`;
                lognum=$(($lognum-1));
                mv $access_log ${logdir}/access_log-$(date -d"- $lognum  days" '+%Y%m%d');

        done

done

Last edited by fpmurphy; 03-20-2009 at 11:49 AM.. Reason: Added code blocks
# 2  
Old 03-20-2009
It appears that the following line is returning an unexpected value
Code:
lognum=`echo $access_log | sed -e 's/.*access_log\.//'`;

You can check by adding a "echo $lognum" statement
# 3  
Old 03-20-2009
Problem solved, had to add something to the script to make sure directories were not empty. Thanks again for your help!
Last edited by forkandspoon; 03-20-2009 at 01:39 PM..
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