Shell Programming and Scripting

Hello. I have a problem with AWK and floats below 0 in a script.
It may be simplified to this line (please, take into account that my "locale" is Spanish, so the system will read "," as decimal separator):

Code:

echo -1,25 2,55745 0,33 ,278 | awk '{print $1+1, $2+1, $3+1, $4+1}'

... getting:

Code:

-0,25 3,55745 1 1

So, what about the third and fourth fields? Why do you think AWK is not reading correctly?

I have tried different options (also with printf options), but I am always at the same point: if the number is 0,xxx AWK will not read the decimal part.
Thank you very much in advance,

Try:

Code:

awk '{printf("%.2f %.2f %.2f %.2f\n", $1+1, $2+1, $3+1, $4+1)}'

Regards

No, It seems not to be working ok. I think that my spanish "locale" configuration may be related with the cause. But maybe any solution involving "format" specification in the inputs?.
As far I know, AWK stores data as 'strings', and makes automatically the numeric conversion if a valid numeric string is found. So Is there any specific instruction to do it manually? I said, for example, conserve the complete string and make the numeric conversion in a second step?
Many Thanks again.

Try this, first the commas are replaced with dots and after formatting the line (variable s), the dots are replaced with commas:

Code:

awk '{
  gsub(",", ".")
  s=sprintf("%.2f %.2f %.2f %.2f\n", $1+1, $2+1, $3+1, $4+1)
  gsub("\.",",",s);print s}
'

Regards

It must be a problem with the quite old "Red Hat" in the pc I was working in. I have tried the same in an Fedora updated machine and AWK works fine again.
So thank you very much Franklin51.
Regards