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Cron job failure

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# 1  
Old 03-13-2009
Cron job failure
The crontab entry looks like this...
29 13 * * * /usr/bin/mk-find --printf "%D\ %N\n" |

This is just a part of a long statement that has apostrophe in it. I will like to know why does it work at command prompt but fail if set as cronjob?
The error is...
/bin/sh: -c: line 0: unexpected EOF while looking for matching `"'
/bin/sh: -c: line 1: syntax error: unexpected end of file

Regards,
Shantanu Oak
# 2  
Old 03-13-2009
would you mind showing us the complete line?
# 3  
Old 03-13-2009
29 13 * * * /usr/bin/mk-find -h 172.29.0.5 -u root -p passwd --noquote --comment backup --printf "%D\ %N\n" | while read var1 var2; do /usr/bin/mk-parallel-dump --basedir /root/shantanu/215 -h 172.29.0.5 -uroot -p passwd -d $var1 -t $var2; done

It looks for the table comment "backup" and take the backup of only those tables.
# 4  
Old 03-13-2009
'man crontab' yields:
Code:
     The sixth field of a line in a crontab file is a string that
     is  executed  by the shell at the specified times. A percent
     character in this field (unless escaped by \) is  translated
     to a NEWLINE character.

     Only the first line (up to a '%' or end of line) of the com-
     mand  field  is  executed by the shell. Other lines are made
     available to the command as standard input. Any  blank  line
     or  line  beginning  with  a  `#'  is  a comment and will be
     ignored.

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