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how to extract last occurence of the field

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# 1  
Old 03-11-2009
how to extract last occurence of the field
path = /first/second/third/fourth. i want to extract /first/second/third from path.my program something like this ....

path=/first/second/third/fourth
noc=`echo $path|tr '/' '\n'|wc -w`
var='echo $noc|cut -d'/' -f 1-$noc --> is giving error.

why $noc is not working here.any other alternative to extract it.

Thanks
kcp_pavan
# 2  
Old 03-11-2009
Code:
% path=/first/second/third/fourth 
% printf '%s\n' "${path%/*}"
/first/second/third
% printf '%s\n' "${path##*/}"
fourth

# 3  
Old 03-11-2009
Computer
Quote:
Originally Posted by kcp_pavan
path=/first/second/third/fourth
noc=`echo $path|tr '/' '\n'|wc -w`
var='echo $noc|cut -d'/' -f 1-$noc --> is giving error.

why $noc is not working here.any other alternative to extract it.
Hummmm ... you translate "/" in "\n" and after you want to "cut" with the "/" as delimiter ... Smilie

Try this :
Code:
$ path=/first/second/third/fourth
$ var=$(dirname $path)
$ echo $var
/first/second/third

SmilieSmilie
# 4  
Old 03-12-2009
reply
both soultions worked effectively. thanks to Goldorakk and radoulov .......

one more sol :
------------------
path=/first/second/third/fourth

echo $path | nawk '{print $NF}' FS="/" | read FILE
echo "File Name: "$FILE --> fourth

echo ${path%/*} | read PAT
echo "Path: "$PAT --> /first/second/third

Smilie
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