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Shell Programming and Scripting

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# 1  
Old 03-10-2009
bash shell
#!/bin/bash
declare -a dirs
index=0
for dir in `ls -d */`
do
dirs[$index]=$dir
echo $index. $dir
index=`expr $index + 1`
done

Its giving me distorted output:

c.sh: dirs[0]=1/: No such file or directory
0. 1/
c.sh: dirs[1]=11844/: No such file or directory
1. 11844/
c.sh: dirs[2]=12819/: No such file or directory
2. 12819/
c.sh: dirs[3]=15734/: No such file or directory
3. 15734/
c.sh: dirs[4]=16217/: No such file or directory
4. 16217/

How can I fix this
# 2  
Old 03-10-2009
I get no such error:

Code:
$ ls -ltR
.:
total 8
-rwxr-xr-x   1 xxxxx    xxxxx     127 Mar 11 02:18 bsh.sh
drwxr-x---   2 xxxxx    xxxxx      96 Jun 25  2008 one
drwxr-x---   2 xxxxx    xxxxx      96 Jun 25  2008 two

./one:
total 0
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 one.rar
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 three.rar
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 two.rar

./two:
total 0
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 five.rar
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 four.rar
-rw-r-----   1 xxxxx    xxxxx       0 Jun 25  2008 six.rar
$ cat bsh.sh
#!/bin/bash

declare -a dirs
index=0
for dir in `ls -d */`
do
dirs[$index]=$dir
echo $index. $dir
index=`expr $index + 1`
done
$ bsh.sh
0. one/
1. two/

# 3  
Old 03-10-2009
That is because of you have higher (2.5) version of bash. My issues is that I need to display list of directories under a path and then take the user input to navigate so I need an array else it would become difficult.

Not sure what other solution I can avail
# 4  
Old 03-10-2009
Can you know my bash version by looking at output of echo?!! Thats kewl man...

Code:
$ bash --version
GNU bash, version 2.03.0(1)-release (sparc-sun-solaris)
Copyright 1998 Free Software Foundation, Inc.

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