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How to fetch running/failed process

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# 1  
Old 03-06-2009
How to fetch running/failed process
I am trying to fetch failed process but while doing that unable to do so. like;

(1)ps -ef | grep snmpCollect

o/p is coming like -

root 12423 4393 1 19:44:06 pts/0 0:00 grep snmpCollect

(2)ps -ef | grep sttps

o/p-

root 15517 4393 0 19:53:24 pts/0 0:00 grep sttps
root 10900 10822 5 13:02:43 ? 1:38 sttps -P -k segRedux=true

That means process snmpCollect is not running and process sttps is running.


Now ,I want a logic that tell process snmpCollect is not running

For that,I am trying following command-

p_name=`ps -ef | grep $process_name | grep -v "grep" | awk '{print $9}'`

if [[ -n $p_name ]];
then
echo "$process_name is Running "
else
echo "$process_name is Down"
fi


but this one is not working properly.I know there is something I can do with awk.


Thanks in advance!!!!
# 2  
Old 03-06-2009
Do you want another way to test if the process is running ?

Try this:

Code:
ps -ef | grep $process_name | grep -v "grep" > /dev/null 
if [ $? -eq 0 ]
then
    echo "$process_name is Running "
else
    echo "$process_name is Down" 
fi

# 3  
Old 03-06-2009
thnx yaar !!! thats working


one more thing what the significance of >/dev/null

whr can I see that??
# 4  
Old 03-06-2009
Code:
 
ps -ef | grep $process_name | grep -v "grep" > /dev/null

Since I'm testing the exit code of the command ($?) I don't really need the output so I send it to /dev/null which is a kind of garbage can.

exit code 0 means the command ends successfully ( find a process in this case) other value may mean different thing depends on the command.
# 5  
Old 03-06-2009
Quote:
Originally Posted by ce9888
Do you want another way to test if the process is running ?

Try this:

Code:
ps -ef | grep $process_name | grep -v "grep" > /dev/null 
if [ $? -eq 0 ]
then
    echo "$process_name is Running "
else
    echo "$process_name is Down" 
fi

'man ksh' yields the following:
Code:
     ?     The decimal value returned by the last  executed  com-
           mand.

In your case 'grep -v grep'
# 6  
Old 03-06-2009
Quote:
Originally Posted by vgersh99
'man ksh' yields the following:
Code:
     ?     The decimal value returned by the last  executed  com-
           mand.

In your case 'grep -v grep'
Logicaly you are right how can you explain this :

Code:
ce9888$ ps -ef | grep -i fiha                                
    user  37558      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
  ce9888  41702  50948   0 10:57:09 pts/12  0:00 grep -i fiha 
    user  56818      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  65156      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  66926      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    user  67088      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  67470      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  68270      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    user  68366      1   0 08:50:57      -  0:34 /home/s/sys/fiha  
    user  68980      1   0 08:50:57      -  0:00 /home/s/sys/fiha
    user  72298      1   0 08:50:57      -  0:05 /home/s/sys/fiha
ce9888$ echo $?
0

Code:
ce9888$ ps -ef | grep -i fiha | grep -v grep                 
    user  37558      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    user  56818      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  65156      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    user  66926      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  67088      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  67470      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  68270      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  68366      1   0 08:50:57      -  0:36 /home/s/sys/fiha 
    user  68980      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    user  72298      1   0 08:50:57      -  0:05 /home/s/sys/fiha  
ce9888$ echo $?
0

It reacts as you suggest, since grep -v did find the "grep" string.

Code:
ce9888$ ps -ef | grep -i fiha | grep -v toto
  ce9888  36474  50948   1 11:08:21 pts/12  0:00 grep -i fiha 
    spsy  37558      1   0 08:50:57      -  0:00 /home/s/sys/fiha
    spsy  56818      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    spsy  65156      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    spsy  66926      1   0 08:50:57      -  0:00 /home/s/sys/fiha 
    spsy  67088      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    spsy  67470      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    spsy  68270      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    spsy  68366      1   0 08:50:57      -  0:37 /home/s/sys/fiha  
    spsy  68980      1   0 08:50:57      -  0:00 /home/s/sys/fiha  
    spsy  72298      1   0 08:50:57      -  0:06 /home/s/sys/fiha  
ce9888$ echo $?
0

Accordingly to your assumption this one should have return 1 since grep -v didn't found the "toto" string. which its not the case...
# 7  
Old 03-06-2009
I've observed a very similar behavior under Solaris as well - no, I cannot reconcile it with the 'man' pages and my understanding of pipes/processes.
Maybe others can chime in.
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