Shell Programming and Scripting

Hi ,

My shell script doesnt function properly while executing.

My shell script has the below mentioned code in it.
#!/bin/sh
CD="/usr/bin/cd"
..
..
$CD /
..
..

main intention behind giving the $CD / is to replace the cd command with /usr/bin/cd at the time of program execution.

but this is not working..

I tried by setting PATH to /usr/bin and /usr/sbin but both didnt work..

Could any one please give me a soultion how to make /usr/bin/cd (not just cd ..cd is working fine)working in the code.

Thanks in advance
RaghuDeep Amilineni

small mistake
CD="cd /usr/bin/cd"
now it should run

cd is a built in command not an external command:

Code:

cd /

is sufficient, instead of:

Code:

CD="/usr/bin/cd"
$CD /

Regards

It sounds like maybe you want the "alias" command. Check the man page.

Are you trying to make it so that if the user types "cd" during the session, a different command of your choosing is executed instead of the default "cd" command?

If you read "man cd" you'll see "cd is a built-in command".
Whenever you will try to use /usr/bin/cd or /bin/cd directly, there is no result.

--> Why do you want to replace "cd" by "/usr/bin/cd" ???

cd cannot work as an external command. An external command creates a child process, and a process cannot affect the environment of its parent.

It exists as an external command in order to simplify some wording in the POSIX standard (see <http://www.opengroup.org> for more information).