Shell Programming and Scripting

I wanted to find 30 days old file list from my datafile location named" u01/u02...etc".

Can you be more specific in describing the problem as it is difficult to figure out what you are trying to do by reading your code. Show us typical input.

I wanted to find all old file lists on my linux server.
In the above script i am not passing any input parameters.

When i ran this script , no output is displayed but i know the fact there are files whcih are older than 30 days.

I would like to fix for loop issue which i suspect as error.

Here is a start, first figure out when was 30 days ago..

#!/usr/bin/ksh
DAYS_AGO=30
DAY=`date +%d`
LMONTH=`date +%b`
MONTH=`date +%m`
YEAR=`date +%Y`
DAY_1=`expr "$DAY" - $DAYS_AGO`

if [ $DAYS_AGO -ge $DAY ];then
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0) MONTH=12;YEAR=`expr "$YEAR" - 1` ;;
esac
DAY_2=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
DAY_Diff=`expr $DAYS_AGO - $DAY`
REAL_DATE=`expr $DAY_2 - $DAY_Diff`
if [ $REAL_DATE = 0 ] ; then
MONTH=`expr $MONTH - 1`
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
fi
fi

MONTH_LEN=`echo $MONTH|wc -c`
echo $MONTH_LEN
if [ $MONTH_LEN -eq 2 ]; then
MONTH="0$MONTH"
fi
DAY_LEN=`echo $DAY|wc -c`
echo $DAY_LEN
if [ $DAY_LEN -eq 2 ]; then
DAY="0$DAY"
fi
case $MONTH in # set month name
01) LMONTH="Jan";;
02) LMONTH="Feb";;
03) LMONTH="Mar";;
04) LMONTH="Apr";;
05) LMONTH="May";;
06) LMONTH="Jun";;
07) LMONTH="Jul";;
08) LMONTH="Aug";;
09) LMONTH="Sep";;
10) LMONTH="Oct";;
11) LMONTH="Nov";;
12) LMONTH="Dec";;
esac
echo "$YEAR/$MONTH/$DAY $LMONTH"

I have a directory with about 20 sub directories in it that has a thousands of files in them all together, I need a script to find what is the oldest file and show date and time created in which ever one of these sub directories.

Will anybody able to help me ?

hi msullivan, would you mind to share how to make past 3 days ?
I was trying to make change of DAY_AGO=3, it doesn't work at all.