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Passing Variable in sed

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# 1  
Old 03-02-2009
Passing Variable in sed
Dear All,
I want to print a file.
First I tried with this
sed '2q;d' filename
it worked. But when i put following it is not working
x=2;
sed '$xq;d' filename

Would any one suggest how to pass the variable?
# 2  
Old 03-02-2009
awk alternative
Same stuff can be done using awk as below.

Code:
awk -v var=$x '{if(NR==var) print $NR}' filename

# 3  
Old 03-02-2009
bash-2.05$ echo $x
2
bash-2.05$ awk -v var=$x '{if(NR==var) print $NR}' uvc_sample_1.txt
awk: syntax error near line 1
awk: bailing out near line 1


is not working Smilie
# 4  
Old 03-02-2009
You may try using any other awk variant (like nawk)
# 5  
Old 03-02-2009
Hi,

Try using :
sed "$xq;d" filename

It should work.
# 6  
Old 03-02-2009
Code:
sed "$x"q filename

# 7  
Old 03-02-2009
Code:
sed "${x}q;d" filename
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