Shell Programming and Scripting

I have a txt file like below:

testin.txt

AB
BC
CD
DE

I have the following awk script

BEGIN {flag1="N"}
/(AB)|(BC)|(CD)|(DE)/ {flag1="Y"}
END {print flag1}

>awk -f testin.awk testin.txt

Returns
Y

I need to set the flag as Y if all the expressionz, i.e. AB, BC, CD and DE exists. I tried giving & and &&. But it didn't work out.

I am very new to awk. Can someone please help?

Hi,

below one might help you!!!!

awk '{if(/(AB)|(BC)|(CD)|(DE)/)then;print"Y"}' testin.txt

Thanks
Sha

Hi..

isn't this an OR condition? What I need is that if all the expressions, AB, BC, CD and DE should be present in the file, then it should set flag as 'Y'

..
OR condition:

awk '{if(/(AB)|(BC)|(CD)|(DE)/)
{print "Y"}
else
{print "N"}}' input.lst

Thanks
Sha

sorry...i don't get this....

what I think this will do is that if(either of the expressions are present), then set to Y; else set to N.

What I need is if (all expressions are present), then set to Y;else set to N.

Try this:

Code:

$ cat buf1
AB
BC
CD
DE
$ echo -e 'AB\nBC\nCD\n' | cmp -s - buf1 && echo 'Y'
$ echo -e 'AB\nBC\nCD\nDE' | cmp -s - buf1 && echo 'Y'
Y

Thanks for the replies...I got over it by declaring a counter. Since I have to do it for a big file, the way with the counter is working pretty well...thanks for the replies..