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ksh scripting ... get previous date

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# 1  
Old 02-13-2009
Question ksh scripting ... get previous date
hi all,
i am developing a korn shell script. One of the requirement is to generate the date, which is 7 days before the current date, and create a folder with that date.

So for ex: if the time command returns 13 Feb 2009, I should be able to generate 6 Feb 2009, and assign that to a variable.

my OS is AIX

can someone post or help me with some working code.

All help is greatly appreciated. I am working under a very tight deadline.

thanks
# 2  
Old 02-13-2009
Hammer & Screwdriver Not quite, but close
Code:
> touch file170
> currd=`stat -c %Y file170`
> change=60*60*24*7
> lastd=`echo "$currd - $change" | bc`
> echo $(date '+%m %d %Y' -d @$lastd)
02 06 2009

Just need to think of the formatting to have the month as Feb.
# 3  
Old 02-13-2009
Hammer & Screwdriver Here is the rest...
Code:
> echo $(date '+%b %d %Y' -d @$lastd)
Feb 06 2009
> myvar=`echo $(date '+%b %d %Y' -d @$lastd)`
> echo $myvar
Feb 06 2009

# 4  
Old 02-13-2009
this is what i get when i run the code.
maybe stat is not recognized on my system
any suggestions

nis3.scr[4]: stat: not found
Invalid character in date/time specification.
Usage: date [-u] [+Field Descriptors]
# 5  
Old 02-13-2009
If you have perl:
Code:
days_ago()
{
  perl -e  '
	# take 86400 * # of days from right now in epoch seconds
		 $yestertime = time - (86400 * $ARGV[0]);
		 $month = (localtime $yestertime)[4] + 1;
	# day of the month
		 $day = (localtime $yestertime)[3];
	# year
		 $year = (localtime $yestertime)[5] + 1900;
	# US format mm dd yyyy
		 printf( "%02d %02d %4d\n", $month, $day, $year);  '  $1
}

#usage
# yesterday
days_ago 1
printf "last week  was %s\n" "$( days_ago 7 )"

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