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finding field count escaping the blank values

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# 1  
Old 02-12-2009
finding field count escaping the blank values
Hi All

I have a file.Below are few records of the file.

sample.txt

CPS,ES,843232910001,ESF81462,W N LINDSAY LTD,01674840629,09-FEB-2009,23-FEB-2009,CDR735,ALL CALLS,01674840629
CPS,ES,843232670001,ESF81462,W N LINDSAY LTD,01674840629,09-FEB-2009,23-FEB-2009,CDR734,ALL CALLS,01674840608

I need to find the count of the 6th field and it should not consider the blank and null values.

say if the total number of records are 10 and in that the 6th filed has 4 values and others are blank then it should give only count as 4 and not 10.

Kindly let me know how to proceed.

Thanks
# 2  
Old 02-12-2009
Try this one
cut -d',' -f6 sample.txt|tr -d " "|grep -vc "^$"
# 3  
Old 02-12-2009
With awk:

Code:
awk -F, '$6>0{n++}END{print n}' file

Regards
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