Shell Programming and Scripting

I am using the following code:

set LASInputFile = `ls *.[Ll][Aa][Ss] | head -1`
set COMPLine = `grep -i :COMPANY $LASInputFile`


to extract the following line from my input file:


COMP. XYZ Public Company :COMPANY NAME


I now need to extract the full name of the company which may be a single word or multiple words separated by white space as in this example. I study awk and sed but I just can't figure out how to code for this.

Thanks,

Paul H.
Denver

Code:

echo 'COMP. XYZ Public Company :COMPANY NAME' | sed 's/.*:\(.*\)/\1/'
echo 'COMP. XYZ Public Company :COMPANY NAME' | awk -F: '{print $NF}'

Thanks for the help. In both cases, the code extracted the string: "COMPANY NAME". What I'm hoping to get is (in my example) "XYZ Public Company", or whatever (delimited or non-delimited) string appears between "COMP." and ":COMPANY NAME".

Thanks,

Paul H.

Code:

echo 'COMP. XYZ Public Company :COMPANY NAME' | sed 's/^[^ ][^ ]* *\([^:][^:]*\)[ ][ ]*:.*/\1/'

This won't work?

Code:

awk -F: '{print $1}' file_with_list | awk -F. '{print $2}'

Another one with sed:

Code:

sed 's/COMP\. \(.*\) :COMPANY NAME/\1/'

Regards

Why two calls to awk?

Code:

awk -F: '{ split($1,a,"."); print a[2] }' file_with_list