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error in script

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# 1  
Old 02-10-2009
error in script
i am using a shell script where i have to start 20 applications

for (( i = 1 ; i <= 20 ; i++ ))
do
export SMCHOME=/global/app/R1S1A3/RAFS/RAF_$i
$SMCHOME/bin/genraf.exe &> LOG_RAF/RAF_$i.txt &
done

But only the first instance is started and rest are not .
# 2  
Old 02-10-2009
That is because of the missing statement (highlighted in RED) within the for loop

Code:
for (( i = 1 ; i <= 20 ; i++ ))
do
export SMCHOME=/global/app/R1S1A3/RAFS/RAF_$i
$SMCHOME/bin/genraf.exe &> LOG_RAF/RAF_$i.txt &
i= $(( $i + 1 ))
done

HTH, Smilie

Regards,

Praveen
# 3  
Old 02-10-2009
Quote:
Originally Posted by sunpraveen
That is because of the missing statement (highlighted in RED) within the for loop

Code:
for (( i = 1 ; i <= 20 ; i++ ))
do
export SMCHOME=/global/app/R1S1A3/RAFS/RAF_$i
$SMCHOME/bin/genraf.exe &> LOG_RAF/RAF_$i.txt &
i= $(( $i + 1 ))
done

No, that's taken care of by the for loop (otherwise there would be a syntax error). I suspect the shell parses the redirection incorrectly. Try writing it like this:
Code:
for (( i = 1 ; i <= 20 ; i++ ))
do
    export SMCHOME=/global/app/R1S1A3/RAFS/RAF_$i
    ${SMCHOME}/bin/genraf.exe > LOG_RAF/RAF_${i}.txt &
done

# 4  
Old 02-10-2009
Thanks a lot its working now
# 5  
Old 02-10-2009
Pludi,

Quote:
No, that's taken care of by the for loop (otherwise there would be a syntax error). I suspect the shell parses the redirection incorrectly. Try writing it like this:
Thanks for pointing that out! A gaffe, if ever there was one! Smilie
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