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# 1  
find max number

Hi, i have a file with numbers in it and i was wondering if there's a script i could use to find the max number and have that printed to a new file?

example a.txt

18
26
47
34
27

so find the max number in a.txt and print it to b.txt.

Thanks!
# 2  
man sort
# 3  
Code:
awk 'n < $0 {n=$0}END{print n}' a.txt > b.txt

Please read the Forum rules and don't ask homework questions.
# 4  
max num. in a file.

Quote:
Originally Posted by moonbaby
Hi, i have a file with numbers in it and i was wondering if there's a script i could use to find the max number and have that printed to a new file?

example a.txt

18
26
47
34
27

so find the max number in a.txt and print it to b.txt.

Thanks!

you can simply use the for loop and get the max no. out of the file: as:

max=1

for in `cat a.txt`
do
if [[ $1 > "$max" ]]; then
max=$1
echo "$max" > b.txt
fi
done

Hope this will work to you.
Thanks
Varun GuptaSmilie
# 5  
Quote:
Originally Posted by varungupta
you can simply use the for loop and get the max no. out of the file: as:

max=1

for in `cat a.txt`
do
if [[ $1 > "$max" ]]; then
max=$1
echo "$max" > b.txt
fi
done

Hope this will work to you.
Thanks
Varun GuptaSmilie
The echo statement must be after the loop and avoid the useless use of cat:

Code:
max=1

while read i
do
  if [[ "$i" > "$max" ]]; then
    max="$1"
  fi
done < a.txt

echo "$max" > b.txt

Regards
# 6  
sort -r file | head -1 > newfile
# 7  
Quote:
Originally Posted by ranjeetmenon
sort -r file | head -1 > newfile
You should use the -n option to sort numeric values:

Code:
sort -nr file | head -1 > newfile

Regards

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