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Hi ..
USE THIS Command

awk '{gsub(" ","",$0); print $0;}' filename
regards
Manish

space=`df -gt | grep "/fnsspool_a" |awk '{print $5}' |sed 's/%//'`
if [ $space > "60" ]
then
for i in `*.jar`
do
mv $i /publish/archive
done
else
echo "NO SPACE in...

what is the logic ,plz specify clearly..
I am not getting it ...!!

It will work definately ....
for filename of any length
dd=`date +"%Y%m%d"
for i in `ls- lrt`
do
x=`basename $i .out`
mv $i $x_dd.out
done

Try This ,it will work only if you want three character filename
i.e. aaa_20090505.out
It will not work for aaaa.out

dd=`date +"%Y%m%d"`
for i in `ls -lrt`
do
x=`echo $i | cut -c 1-3`...

use
ftp -inv $IPADDRESS << EOF

use
grep "internet" * or To be more specific use grep -l "internet" *

The previous logic will pick files from test.log,you need not to specify filenames one by one manually.It will read line by line from test.log and ftp them ..
while IFS= read -r line
do
ftp...

Also Try This,It will take one by one file and ftp them.
It may require some modification this is just a logic
while IFS= read -r line
do
ftp IPADDRESS
put $line
bye
done < test.log

Try This...
Your file will be ftpied as a regular file,even if contains 300 files.
Better zip it and ftp.but if you are zipping then send in binary mode.
read $filename
ftp -inv $IPADDRESS << EOF...

Try This ...

sed "s/\.\/tmp/\/home\/tmp/g" filename > newfile

I am also new to shell scripting can you tell me ..
why are you using "\" in /Volumes/Backup\ vipin/

this will print the first matching pattern of a file ..

sed -n '/John/{p;q;}' test1.txt