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Hi All,

I came across a weird scenario which i couldnt explain why.
As part of script which is run as /bin/sh shebang, we are trying to check if there is any process that runs with the same name...

I can give you an idea of how it can be done assuming that you want to change some details on this specific line in the cron file of all 60 servers,

You can run the below commands with ssh,
1....

You can also try below,


cat input.txt
1 3 4 5 6
3 6 7 8 3 5
2 3 5 6
2 3
1 4 5 6 8 9 9 4



split -l 2 -a 2 input.txt "Splitfile_"




Splitfile_aa
Splitfile_ab
Splitfile_ac

varathaneie: Please add relevant information here and not simply post links to other sites, especially with just a handful of posts here.

It was a good info which i never knew...Will try something on this...Thanks a lot :-)

To get exact ouptu as you want with the the file name for which you are trying to get,


awk '{ line++; } END { print FILENAME" "line}' filename

How do i connect when i want to do automation which involves connecting from windows(win 7) to unix?

I believe FTP will not let us run any UNIX commands for our automation

Assuming you have perl option,

ls *S1STC* | perl -nle '$x=$_;s/S1STC/S2STC/;system "cp $x $_"'

Or if you want a looping structure, use below code,

#!/bin/sh
for foobar in `ls *S1STC*`;...

Hi Nawrajesh,

Try to remove the below lines from your code


exit ;
break;;


and replace it with

echo "End of Seclection" ;;

It worked fine for me while testing.

var=`ls -d */*.o | grep -v vwin`

Now var has the value of all the *.o files

Try the below command

sed -n 's/<Key>\(.*\)<\/Key>/\1/p' filename

For long listing
ls -lrt *PROMOTION* | grep -v LEN

For just FIlename
ls *PROMOTION* | grep -v LEN

Hi Pravin,

Is it possible for you to explain the awk commadn which u have provided...

If in case you want to get only the top 10 directories in the current directory, you can try below command,

du /usr/ | sort -rn | awk 'NR>=2&&NR<=10 { print $2"\t" $1 }'

if u want to work with all the files in the current directory, you may to use a looping structure,
ls > ./list.txt
while read line
do
sed "/#Text_to_be_deleted/d" $line >tmp
mv tmp $line...

Hope this also gives the same output which is easier to understand,

echo "datarecords.txt: male | datarecords.txt: male | datarecords.txt: female" | sed 's/datarecords.txt//g'