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What is the need for me to joke here ?

Words you have used really have taken me aback.

Ok. coming to the point with your example.

try this first and then the later solution

echo "aa\naa"...

Changing to print c doesn't help.

It should be changed to the below as I had posted earlier . :)

awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}'...

This is absolutely working as expected.

Input is
aa<space>
aa

only the pattern in second line "aa" matches and not the one in the first line.

:)

there is one more problem with that

with the input posted by Shell and for search pattern as "aa" it would match "aaa" also

try this,
awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } }...

Here,

print statement should have been

print ++c