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Thanks a lot it is working fine :)

count is dispalying as expected ,but i need to store the values into one variable for comparsion purpose.

thanks for quick reply and it is working fine and small help to assign the value to variable. it not getting output

cnt=`echo "[${g_count}]" |wc -l`

Thanks for quick reply

mk@test2
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Hi Team,
below sql rerturn 20 records, the result set i am going to assign to one variable and it showing count is 1.
and i don't use count() in sql query... based on count, i need to fail the...