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Thank you Yoda, I was thinking like if I will use grep
command with ls then it may get some other results too, so I have used awk.

But your given solution is working well and fine.:)

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Hello,

Following code may help to find the requirement please.


$ ls -ltr | awk '{print $9}' | awk -vch="1" '{if(substr($0,3,ch) ~ "b") print $0}'


Output will be as follows.

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