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The awk checks field 3 (etime) against a regular expression (RE) that checks the digits before a - character. But - I misread your first post - that's days, not hours!
Also there is a bug in the RE,...

I wonder what the -f does in conjunction with -o ...
"etime" is standard. With an appropriate RE:
ps -eo pid,comm,etime | awk '$3~/^[2-9][0-9]*-/{print $1,$2,$3}'