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GNU awk

awk 'BEGIN{
numdays = 86400 * 5
now=systime()
}
{
m=split($(NF-1),a,"-")
yr=a[1]
mth=a[2]
day=a[3]
t1=mktime(yr" "mth" "day" "00" "00" "00)
if ( (now - t1) >...

which one is column 10?