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Cheers! It's been a long long day. :(

Doh! So I am. The question still stands though -

test -w . ; echo ?

just returns "?" now

From within a directory, how do I determine whether I have write permission for it.

test -w pwd ; echo ?

This doesn't work as it returns false, even though I have write permission.

I'm afraid neither of those two solutions work. Both still print the error message, with the added bonus of yours producing a question mark as well, Vino.

That doesn't work. It still outputs that -j is an invalid option

Working in a bash environment, in the following example, how do I direct the error message that putting in an invalid flag (-j for example) would normally produce to dev/null?

while getopts "abcd"...

Thanks for your help Ygor. That's neater than the alternative I came up with.

I have a variable which consists of a string like this:

001 aaabc 44 a bbb12

How do I extract each substring, delimited by the spaces, into new variables - one for each substring?

eg var1...

I have a loop which will go round "i" number of times and return a value each time. Is there a way to set a variable(i) such that I will end up with variable(1), variable(2), variable(3) etc. for...

Thanks gauravgoel, that was just what I was looking for. Thanks for your effort as well, vino.

Thanks for your reply, but I want it to loop through the string and then perform an action for each occurrance of r, not just once. eg. "rover" would return 11 in this example because there're two...

I am attempting to pass a string into awk and loop through it, and then for every occurrance of a certain character perform an action. In this case, for example, echo 1 for each time character r is...

Thanks Ygor. That was exactly what I was looking for. I only spent about 8 hours trying to figure it out yesterday! :confused:

Right. I'm in a bash shell. Any ideas about how I go about it in that?

Okay, I've been playing around with the command you gave me, matrixmadhan, but I can't figure out how to print the fields $1, $2, $3 etc to different variables. They always either end up in the first...

Excellent. Thanks a lot!

If I do "ls -l filename" in a script, it should return something like this:

-rw-r--r-- 1 user group 5945 Feb 28 14:24 filename

How do I put each of the above strings into a different...

I'm a complete newbie at UNIX. I have an exercise to do where I have to find the username of someone executing a script and print it to another file. I was sort of hoping for a command like finger,...

Thanks for your reply. Now all I have to do is figure out how to use getlogin()

:confused:

Suppose there is a file which is being executed by someone. Is there a way to return the username of whoever is using that file?

Yep, that works a treat. Thanks a lot tmarikle.

file1 is four lines "line 1, line 2, line 4, line 5"

I want to introduce a new line.

For example, this works:

sed '/2/a\
line 3' file1

This doesn't

variable=2
sed "/\$variable/a\...

Nope, still no result.

Afraid not; it gives me this error message if I replace ' with "

sed: -e expression #1, char 10: Extra characters after command

I'm attempting to append a line after a specific address with sed. If I type in the address eg.3 then it will append after the third line. I can't get it to work with a variable though. Does anyone...