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No, it does not work for me. Tried it again just right now.
I get this:

echo $var
multi\n line\n variable

Thank you very much, appreciate it a lot. Yes, this did the trick, now it works. :) In fact, I don't even have to put "\n" when it's called like this.

I'm using the Bash shell.

Thank you. I do this, than I do an "echo $var1" and this is what I get:

more \n than \n one \n line

I think the single quotes tells it to ignore the returns. When I use double quotes, I still...

Hi, this is probably very easy but, how do I define a variable for more than one line.

For example:

var1='more
than
one
line'

when I call it, I want it to be exactly like this, don't...