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Can someone provide some assistance with this. I'm trying to install vmware server but it's not going so well.

$ uname -a
Linux testunix 2.6.33.6-147.2.4.fc13.i686.PAE #1 SMP Fri Jul 23 17:21:06...

oh yea, forgot to remove it from the $source. That fixed it, thanks man!

whoops cut some of it off in the previous post.

zcat /archive/$ID$date.gz | awk -v src=$source '{FS = "^"} {if($2==$src) {print $1}}' | awk '{print $7}' | sort | uniq -c | sort -n

Why would doing it like this provide no results?

zcat /archive/$ID$date.gz | awk -v src=$source '{FS = "^"} {if($2==$src) {print $1}}' | awk '{print $7}' | sort | uniq -c | s$

So I have a if statement inside an awk to check if $2 of a awk equals a specific IP but the test fails. So here is what I have.

# !/bin/sh
echo "Enter client ID"
read ID

echo "Enter month...

bah, nevermind i just tossed it into the background using &

Ok, I have written a main script which checks a directory contents every 30 secs then sleeps. The subscript does a usermod, if the user is logged on, it sleeps for 30 secs and then trys again over...

hehe oh yea, maybe I should give up scripting while I am ahead. :p

Is there a way that I can make the following work with using variables?

perl -pi -e 's#blah#hrm#ig' replacetext

but like this

var=blah
perl -pi -e 's#$var#hrm#ig' replacetext

I am trying to write a script that does a useradd -G <group> <user> but you cannot modify the user if he/she is logged on. How could I check to see if the user is on or if the user has been added to...

file.dat contains
blah/hah

running the following at the shell prompt it works
$grep 'blah' file.dat | cut -d '/' -f 2
hah...