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thanks for the alternatives..but a few doubts follow
(n i must sincerely thank u guys for the help)

1.isnt the way i gave the command ie :
eval echo \$p[12]

alright? i believe this will be...

1.
on prompt,i wrote
eval echo \$p[12]

ive defined p1 n p12 as variables n i wanted their values to be printed on the screen but this did not happen.
how else can i acheive the same result with...

perderabo has answered my query..plz look into his explaination..thanks anyways

hey thanks brother

but ur simple answer made me look stupid !

so it is actually left to the kernel to interpret the metachars in case of grep coming eith a " " for the pattern, is it?

heres the o/p from echo:

dsadm@punbi1:/apps/dsadm/Practice/abhi/unix> echo a* a1

a1 a11 a1s a1sd a2 a3 a4 a5 ans as a1

dsadm@punbi1:/apps/dsadm/Practice/abhi/unix> echo "a*" a1

a* a1

need help with grep :
down below a11,a1s,a1 r files and for ur info,there r other files also with "a" as their first letter

dsadm@punbi1:/apps/dsadm/Practice/abhi/unix> grep a* a1

a11:this is...

need help with grep :
down below a11,a1s,a1 r files and for ur info,there r other files also with "a" as thier first letter

dsadm@punbi1:/apps/dsadm/Practice/abhi/unix> grep a* a1

a11:this is...

thanks for the reply...
n another few if u dont mind...

1.
i tried the command below n the error msg following it was generated.how do u interpret the error msg?
...

what will the cmd below do?
ls *.[Mm][Pp]3

1 members mentions that to seek all permutations and combinations of the mp3 extension ill have to use curly braces, {} and not, [].
what then will []...