Search Results

This works great - thanks

What I need to do is to be able to echo 'DATE incorrect' if it is not 8 digits long or 'DATE correct' if it is..any ideas how to do this..

many thanks

#!/bin/sh

date1=01234567

echo $date1

echo $DATE | sed -n -e '/^[0-9]\{8\}$/p'

>> this produces the following

01234567
./check.sh: /: cannot execute
./check.sh: [0-9]{8}$/p: not found...

Just to clarify my previous post - is there any function within UNIX that would allow me to check if something is 8 digits long etc. apart from grep

#!/bin/sh

L=0

test()
{
while read line
do

l='expr $L + 1'
echo $L

done

echo $L
}

test < test.sh

Firstly - aplogies to Vino

I need to check wether or not a variable called DATE is actually a date by doing the following - checking it is all numeric and secondly checking if it is 8 digits long....

Hi guys,

does anyone know how to test for a regular expression - i want to include it in a script to make sure the variable is a regexp

cheers

#!/bin/sh

L=0

while read line
do

L=`expr $L + 1`
echo $L

done < dinseh.sql

echo $L

This still produces 0

Hi guys,

does anyone know how to test for a regular expression - i want to include it in a script to make sure the variable is a regexp

cheers

Hi,

This produces an error: L=$((L+1))


also i only mixed up the 1's and L's when copying it onto the forum

cheers

L=0

cat test.sh | while read line
do

L='expr $1 + 1'
echo $L

done

echo $l


>>> the echo $L at the end produces 0 but i actually want it to produce the number of lines - any idea why...

Could anyone please explain what the 2a3 is for below?

Is there anyway to just get the differences without the 2a3 and 4,5d4


Thanks

Hi,

I've got two files A and B

File A: File B:

1;2;a;4;5 1;2;1;a;4;7
3;2;b;d;s 3;3;1;b;5;1
e;2;c;s;w l;8;4;d;5;s
4;3;f;w;q ...

Hi,

I have a file as follows:

4047241;20050201;999;12345
5642154;20050202;123;56456

What I need to do is to take each of the fields (delimited by ";") and return the following

...

Hi,

Does anyone know what happens when two processes are simultaneously trying to write to a single file in UNIX (AIX)?

Cheers

This is the format of output.txt:

COEC2372323|EC2372323|7128778| |BE0117013319|381666|180617

and this is the format of assets.dat
...

Is that because of the FNR statement?

What I need to do is compare two files, third field of the first file (field seperator "|") and the 2nd field of the second file (field seperator ";")
...

:confused:

Thanks for your response - sorry yes I meant the record seperator, from reading the man pages i'm aware you can change it within an awk statement - its just that I can't find examples...

Hi,

I have two files each with different record seperators, one with a pipe | and the other with a semi-colon ;

How do you deal with this in awk?

Any help appreciated

specifically i need...

Hi,

I've been given the statement below which I understand, apart from the section {arr[$3]=1;next} - if anyone can shed any light on this that would be great

awk -F\;...

I am only asking about this part of the AWK statement:

arr[$3]=1;next

cheers

Hi,

Could anyone please explain why we have arr[$3]=1 - what does this statement do?

awk -F\; 'FNR==NR{arr[$3]=1;next};$3 in arr' core.txt gmrd.txt

Any help appreciated

Those links were very useful, Could anyone tell me why we set FNR=NR
I know what they mean, I just can't see why this would be done

Cheers

Is anyone able to explain what vgersh99 has done above? I'm new to scripting and am finding it immensly difficult trying to figure out what the following statement does exactly:

awk '
BEGIN {...

does anyone know what $? means? i echoed it on my box (running AIX Korn shell) and got 127