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I get an expr syntax error. here is my code


#!/bin/sh
echo 'Enter a number: \c'
read number

echo $number > test #copy value in number to file test

decimal=`wc -m...

Is there a utility or command I can use to tell the number of decimal places a number has. For instance, if the number is 432, it will give hundred as the number of decimal places.

I need to make a small script that figures out if a filename that the user enters is a file or a directory. and if it is a directory, how many files are in it.

please point me to the right...

works great! thanks

im trying to change the format of a list of numbers to xx-xx-xx. how do I do this?

list of numbers:
567890
56 78 90
(56)-7890
(56)-78-90
(56) 78 90


I want these numbers to be converted...

thanks guys!

I think the list of words is the built in dictionary in Unix. It is located in /usr/dict

the list goes like this:

Animal
Beer
category

etc....

I tried doing:

grep '[t.......t*'...

What is the syntax for using the grep utility to find all 8 character words in a long list of words that contain the letter 't'?